# Line slope calculator 2x+8y=80

**Straight line given by points A[0; 10] and B[8; 8]**

## Calculation:

**Slope-intercept form of line:**y = -0.25x+10

**Canonical form of the line equation:**2x+8y-80 = 0

**Parametric form of the line equation:**

x = 8t

y = -2t+10 ; t ∈ R

**Slope:**m = -0.25

**Slope angle of line: φ =**-14°2'10″ = -0.245 rad

**X intercept:**x

_{0}= 40

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 9.7014

**The length of the segment AB: |AB| =**8.2462

**Vector: AB =**(8; -2)

**Normal vector: n =**(2; 8)

**Midpoint of the segment AB: M =**[4; 9]

**Perpendicular Bisector equation:**8x-2y-14 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (8; 8) ; |OB| = 11.3137**

**Scalar product OA .OB = 80**

**Angle ∠ AOB = 45° = 0.7854 rad**